2.6-bo'lim: Cheksiz limitlar
1-6 muammolar uchun ko'rsatilgan chegaralarni, agar ular mavjud bo'lsa, baholang.
- \(\displaystyle f\left( x \right) = \frac{9}{{{{\left( {x - 3} \right)}^5}}}\) baholash uchun,
- \(\mathop {\lim }\limits_{x \to {3^{\, - }}} f\left( x \right)\)
- \(\mathop {\lim }\limits_{x \to {3^{\, + }}} f\left( x \right)\)
- \(\mathop {\lim }\limits_{x \to 3} f\left( x \right)\)
- \(\displaystyle h\left( t \right) = \frac{{2t}}{{6 + t}}\) baholash uchun,
- \(\mathop {\lim }\limits_{t \to \, - {6^{\, - }}} h\left( t \right)\)
- \(\mathop {\lim }\limits_{t \to \, - {6^{\, + }}} h\left( t \right)\)
- \(\mathop {\lim }\limits_{t \to \, - 6} h\left( t \right)\)
- \(\displaystyle g\left( z \right) = \frac{{z + 3}}{{{{\left( {z + 1} \right)}^2}}}\) baholash uchun,
- \(\mathop {\lim }\limits_{z \to \, - {1^{\, - }}} g\left( z \right)\)
- \(\mathop {\lim }\limits_{z \to \, - {1^{\, + }}} g\left( z \right)\)
- \(\mathop {\lim }\limits_{z \to \, - 1} g\left( z \right)\)
- \(\displaystyle g\left( x \right) = \frac{{x + 7}}{{{x^2} - 4}}\) baholash uchun,
- \(\mathop {\lim }\limits_{x \to {2^{\, - }}} g\left( x \right)\)
- \(\mathop {\lim }\limits_{x \to {2^{\, + }}} g\left( x \right)\)
- \(\mathop {\lim }\limits_{x \to 2} g\left( x \right)\)
- \(\displaystyle h\left( x \right) = \ln \left( { - x} \right)\) baholash uchun,
- \(\mathop {\lim }\limits_{x \to {0^{\, - }}} h\left( x \right)\)
- \(\mathop {\lim }\limits_{x \to {0^{\, + }}} h\left( x \right)\)
- \(\mathop {\lim }\limits_{x \to 0} h\left( x \right)\)
- \(\displaystyle R\left( y \right) = \tan \left( y \right)\) baholash uchun,
- \(\mathop {\lim }\limits_{y \to {{{\textstyle{{3\pi } \over 2}}}^{\, - }}} R\left( y \right)\)
- \(\mathop {\lim }\limits_{y \to {{{\textstyle{{3\pi } \over 2}}}^{\, + }}} R\left( y \right)\)
- \(\mathop {\lim }\limits_{y \to {\textstyle{{3\pi } \over 2}}} R\left( y \right)\)
7 va 8 masalalar uchun berilgan funksiyaning barcha vertikal asimptotalarini toping.