2.10-bo'lim: Limitning ta'rifi
Quyidagi chegaralarni isbotlash uchun chegara ta'rifidan foydalaning.
- \(\mathop {\lim }\limits_{x \to 3} x = 3\) Yechim
- \(\mathop {\lim }\limits_{x \to - 1} \left( {x + 7} \right) = 6\) Yechim
- \(\mathop {\lim }\limits_{x \to 2} {x^2} = 4\) Yechim
- \(\mathop {\lim }\limits_{x \to - 3} \left( {{x^2} + 4x + 1} \right) = - 2\) Yechim
- \(\displaystyle \mathop {\lim }\limits_{x \to 1} \frac{1}{{{{\left( {x - 1} \right)}^2}}} = \infty \) Yechim
- \(\displaystyle \mathop {\lim }\limits_{x \to {0^ - }} \frac{1}{x} = - \infty \) Yechim
- \(\displaystyle \mathop {\lim }\limits_{x \to \infty } \frac{1}{{{x^2}}} = 0\) Yechim