7.1-bo'lim : Qismlar bo'yicha integratsiya
8. \( \displaystyle \int{{{y^6}\cos \left( {3y} \right)\,dy}}\) ni baholang.
Yechim
Xo'sh, bu muammo bilan qismlar bo'yicha integratsiyaning "standart" usulini bajaring (i.e. \(u\) va \(dv\) ni tanlash va formuladan foydalanish) biroz vaqt talab etadi. Shunday qilib, bu jarayonni qisqartirish uchun eslatmalarda ko'rgan jadvaldan foydalanish yaxshi muammoga o'xshaydi.
Mana bu muammo uchun jadval.
\[\begin{array}{rrr} {{y}^{6}} & \cos \left( 3y \right) & + \\ 6{{y}^{5}} & \displaystyle \frac{1}{3}\sin \left( 3y \right) & - \\ 30{{y}^{4}} & \displaystyle -\frac{1}{9}\cos \left( 3y \right) & + \\ 120{{y}^{3}} & \displaystyle -\frac{1}{27}\sin \left( 3y \right) & - \\ 360{{y}^{2}} & \displaystyle \frac{1}{81}\cos \left( 3y \right) & + \\ 720y & \displaystyle \frac{1}{243}\sin \left( 3y \right) & - \\ 720 & \displaystyle -\frac{1}{729}\cos \left( 3y \right) & + \\ 0 & \displaystyle -\frac{1}{2187}\sin \left( 3y \right) & - \\ \end{array}\]2-qadam
Mana bu muammoning ajralmas qismi,
\[\begin{align*}\int{{{y^6}\cos \left( {3y} \right)\,dy}} & = \left( {{y^6}} \right)\left( {\frac{1}{3}\sin \left( {3y} \right)} \right) - \left( {6{y^5}} \right)\left( { - \frac{1}{9}\cos \left( {3y} \right)} \right) + \left( {30{y^4}} \right)\left( { - \frac{1}{{27}}\sin \left( {3y} \right)} \right)\\ & \,\,\,\,\,\,\,\,\,\,\,\,\, - \left( {120{y^3}} \right)\left( {\frac{1}{{81}}\cos \left( {3y} \right)} \right) + \left( {360{y^2}} \right)\left( {\frac{1}{{243}}\sin \left( {3y} \right)} \right)\\ & \,\,\,\,\,\,\,\,\,\,\,\,\, - \left( {720y} \right)\left( { - \frac{1}{{729}}\cos \left( {3y} \right)} \right) + \left( {720} \right)\left( { - \frac{1}{{2187}}\sin \left( {3y} \right)} \right) + c\\ & = \require{bbox} \bbox[2pt,border:1px solid black]{\begin{align*} & \frac{1}{3}{y^6}\sin \left( {3y} \right) + \frac{2}{3}{y^5}\cos \left( {3y} \right) - \frac{{10}}{9}{y^4}\sin \left( {3y} \right) - \frac{{40}}{{27}}{y^3}\cos \left( {3y} \right)\\ & \hspace{0.5in} + \frac{{40}}{{27}}{y^2}\sin \left( {3y} \right) + \frac{{80}}{{81}}y\cos \left( {3y} \right) - \frac{{80}}{{243}}\sin \left( {3y} \right) + c\end{align*}}\end{align*}\]