Asosiy tarkibga o'tish

1.3-bo'lim : Trig funktsiyalari

8. Kalkulyatordan foydalanmasdan \(\displaystyle \tan \left( { - \frac{\pi }{3}} \right)\) ning aniq qiymatini aniqlang.

Yechim

Ushbu muammoni hal qilish uchun biz shuni ta'kidlashimiz kerakki, \( - \frac{\pi }{3}\) to'rtinchi kvadrantda musbat \(x\) o'qi bilan \(\frac{\pi }{3}\) burchagini hosil qiladi va biz ushbu muammo uchun quyidagi birlik doirasiga ega bo'lamiz.

A unit circle with the angles \(\frac{\pi }{6}\), \(\frac{\pi }{4}\) and \(\frac{\pi }{3}\) drawn in the first quadrant and labeled with the coordinates \(\left( {\frac{{\sqrt 3 }}{2},\frac{1}{2}} \right)\), \(\left( {\frac{{\sqrt 2 }}{2},\frac{{\sqrt 2 }}{2}} \right)\) and \(\left( {\frac{1}{2},\frac{{\sqrt 3 }}{2}} \right)\) where they meet the circle.  The axes are labeled with the angles 0 and \(2\pi \), \(\frac{\pi }{2}\), \(\pi \) and \(\frac{{3\pi }}{2}\) and the points (1,0), (0,1), (-1,0) and (0,-1).  The angle \( - \frac{\pi }{3}\) is drawn in the fourth quadrant and a dashed vertical line connects the point where it meets the circle to the point for \(\frac{\pi }{3}\), showing the two points have the same \(x\)-coordinate and \(y\)-coordinates that differ only in sign.
2-qadam

\( - \frac{\pi }{3}\) ni ifodalovchi chiziq koordinatalari \(\frac{\pi }{3}\) ni ifodalovchi chiziq koordinatalari bilan bir xil bo‘ladi, bundan tashqari \(y\) koordinatasi endi manfiy bo‘ladi. Shunday qilib, bizning yangi koordinatalarimiz \(\left( {\frac{1}{2}, - \frac{{\sqrt 3 }}{2}} \right)\) bo'ladi va shuning uchun javob:

\[\tan \left( -\frac{\pi }{3} \right)=\frac{\sin \left( -\frac{\pi }{3} \right)}{\cos \left( -\frac{\pi }{3} \right)}=\frac{-{}^{\sqrt{3}}/{}_{2}}{{}^{1}/{}_{2}}=-\sqrt{3}\]