Asosiy tarkibga o'tish

1.3-bo'lim : Trig funktsiyalari

6. Kalkulyatordan foydalanmasdan \(\displaystyle \sec \left( { - \frac{{11\pi }}{6}} \right)\) ning aniq qiymatini aniqlang.

Yechim

Birinchidan, biz \(\frac{\pi }{6} - 2\pi = - \frac{{11\pi }}{6}\) va shunga o'xshash (manfiy burchaklar soat yo'nalishi bo'yicha aylantirilishini esga olib) biz \( - \frac{{11\pi }}{6}\) uchun terminal chizig'i birinchi kvadrantda musbat \(x\) o'qi bilan \(\frac{\pi }{6}\) burchagini hosil qilishini ko'rishimiz mumkin. Boshqacha qilib aytganda, \( - \frac{{11\pi }}{6}\) va \(\frac{\pi }{6}\) bir xil burchakni ifodalaydi. Shunday qilib, biz ushbu muammo uchun quyidagi birlik doirasiga ega bo'lamiz.

A unit circle with the angles \(\frac{\pi }{6}\), \(\frac{\pi }{4}\) and \(\frac{\pi }{3}\) drawn in the first quadrant and labeled with the coordinates \(\left( {\frac{{\sqrt 3 }}{2},\frac{1}{2}} \right)\), \(\left( {\frac{{\sqrt 2 }}{2},\frac{{\sqrt 2 }}{2}} \right)\) and \(\left( {\frac{1}{2},\frac{{\sqrt 3 }}{2}} \right)\) where they meet the circle.  The axes are labeled with the angles 0 and \(2\pi \), \(\frac{\pi }{2}\), \(\pi \) and \(\frac{{3\pi }}{2}\) and the points (1,0), (0,1), (-1,0) and (0,-1).  The line for the angle \(\frac{\pi }{6}\) is also labeled \( - \frac{{11\pi }}{6}\), showing that the two angles end on the same line.
2-qadam

Ikki burchak \( - \frac{{11\pi }}{6}\) va \(\frac{\pi }{6}\) bir xil koordinatalarga ega bo'lgani uchun javob:

\[\sec \left( -\frac{11\pi }{6} \right)=\frac{1}{\cos \left( -\frac{11\pi }{6} \right)}=\frac{1}{{}^{\sqrt{3}}/{}_{2}}=\frac{2}{\sqrt{3}}\]