Asosiy tarkibga o'tish

1.3-bo'lim : Trig funktsiyalari

4. Kalkulyatordan foydalanmasdan \(\displaystyle \cos \left( { - \frac{{2\pi }}{3}} \right)\) ning aniq qiymatini aniqlang.

Yechim

Avval biz \( - \pi + \frac{\pi }{3} = - \frac{{2\pi }}{3}\) ning (manfiy burchaklar soat yoʻnalishi boʻyicha, musbat burchaklar esa soat yoʻnalishi boʻyicha teskari yoʻnalishda aylanishini eslatib oʻtamiz) \( - \frac{{2\pi }}{3}\) uchun terminal chizigʻi uchinchi kvadrantda manfiy \(x\) oʻqi bilan \(\frac{\pi }{3}\) burchagini hosil qilishini payqashimiz mumkin va bu muammo uchun quyidagi birlik doiraga ega boʻlamiz.

A unit circle with the angles \(\frac{\pi }{6}\), \(\frac{\pi }{4}\) and \(\frac{\pi }{3}\) drawn in the first quadrant and labeled with the coordinates \(\left( {\frac{{\sqrt 3 }}{2},\frac{1}{2}} \right)\), \(\left( {\frac{{\sqrt 2 }}{2},\frac{{\sqrt 2 }}{2}} \right)\) and \(\left( {\frac{1}{2},\frac{{\sqrt 3 }}{2}} \right)\) where they meet the circle.  The axes are labeled with the angles 0 and \(2\pi \), \(\frac{\pi }{2}\), \(\pi \) and \(\frac{{3\pi }}{2}\) and the points (1,0), (0,1), (-1,0) and (0,-1).  The angle \( - \frac{{2\pi }}{3}\) is drawn in the third quadrant and lies on the same line through the origin as the angle \(\frac{\pi }{3}\), so the coordinates of the two points on the circle differ only in sign.
2-qadam

\( - \frac{{2\pi }}{3}\)ni ifodalovchi chiziq \(\frac{\pi }{3}\) ni ifodalovchi chiziqning oyna tasviridir va shuning uchun \( - \frac{{2\pi }}{3}\) koordinatalari \(\frac{\pi }{3}\) koordinatalari bilan bir xil bo‘ladi, bundan tashqari ikkala koordinata ham salbiy bo‘ladi. Shunday qilib, bizning yangi koordinatalarimiz \(\left( { - \frac{1}{2}, - \frac{{\sqrt 3 }}{2}} \right)\) bo'ladi va shuning uchun javob:

\[\cos \left( { - \frac{{2\pi }}{3}} \right) = - \frac{1}{2}\]