Asosiy tarkibga o'tish

1.3-bo'lim : Trig funktsiyalari

2. Kalkulyatordan foydalanmasdan \(\displaystyle \sin \left( { - \frac{{4\pi }}{3}} \right)\) ning aniq qiymatini aniqlang.

Yechim

Birinchidan, biz \( - \pi - \frac{\pi }{3} = - \frac{{4\pi }}{3}\) va shunga o'xshash (manfiy burchaklar soat yo'nalishi bo'yicha aylantirilishini eslab qolishimiz mumkin) biz \( - \frac{{4\pi }}{3}\) uchun terminal chizig'i ikkinchi kvadrantda manfiy \(x\) o'qi bilan \(\frac{\pi }{3}\) burchagini hosil qilishini ko'rishimiz mumkin va biz ushbu muammo uchun quyidagi birlik doiraga ega bo'lamiz.

A unit circle with the angles \(\frac{\pi }{6}\), \(\frac{\pi }{4}\) and \(\frac{\pi }{3}\) drawn in the first quadrant and labeled with the coordinates \(\left( {\frac{{\sqrt 3 }}{2},\frac{1}{2}} \right)\), \(\left( {\frac{{\sqrt 2 }}{2},\frac{{\sqrt 2 }}{2}} \right)\) and \(\left( {\frac{1}{2},\frac{{\sqrt 3 }}{2}} \right)\) where they meet the circle.  The axes are labeled with the angles 0 and \(2\pi \), \(\frac{\pi }{2}\), \(\pi \) and \(\frac{{3\pi }}{2}\) and the points (1,0), (0,1), (-1,0) and (0,-1).  The angle \( - \frac{{4\pi }}{3}\) is drawn in the second quadrant and a dashed horizontal line connects the point where it meets the circle to the point for \(\frac{\pi }{3}\), showing the two points have the same \(y\)-coordinate and \(x\)-coordinates that differ only in sign.
2-qadam

\( - \frac{{4\pi }}{3}\) ni ifodalovchi chiziq koordinatalari \(\frac{\pi }{3}\) ni ifodalovchi chiziq koordinatalari bilan bir xil bo‘ladi, bundan tashqari \(x\) koordinatasi endi manfiy bo‘ladi. Shunday qilib, bizning yangi koordinatalarimiz \(\left( { - \frac{1}{2},\frac{{\sqrt 3 }}{2}} \right)\) bo'ladi va shuning uchun javob:

\[\sin \left( { - \frac{{4\pi }}{3}} \right) = \frac{{\sqrt 3 }}{2}\]