2.8-bo'lim : Infinity chegaralari, II qism
8. \(\displaystyle \mathop {\lim }\limits_{z \to \, - \infty } \ln \left( {\frac{{3{z^4} - 8}}{{2 + {z^2}}}} \right)\) ni baholang.
Yechim
Avval e'tibor bering,
\[\mathop {\lim }\limits_{z \to \, - \infty } \frac{{3{z^4} - 8}}{{2 + {z^2}}} = \infty \]Agar siz ushbu cheklovga ishonchingiz komil bo'lmasa, avvalgi bo'limga qaytib, ushbu turdagi limitlarni amalga oshirishingiz mumkinligiga ishonch hosil qilish uchun u erdagi ba'zi misollar bilan ishlashingiz kerak.
Endi eslash 5-misol Ushbu bo'limdan biz bilamizki, argument chegarada cheksiz bo'lganligi sababli javob:
\[\mathop {\lim }\limits_{z \to \, - \infty } \ln \left( {\frac{{3{z^4} - 8}}{{2 + {z^2}}}} \right) = \require{bbox} \bbox[2pt,border:1px solid black]{\infty }\]