Tenglamani nolga tenglashtiring va iloji boricha chap tomonni ko'paytiring.

\[{x^3} + 7{x^2} - x = x\left( {{x^2} + 7x - 1} \right) = 0\]

Shunday qilib, biz bitta ildiz \(x = 0\) ekanligini ko'rishimiz mumkin va kvadratik faktor bo'lmagani uchun qolgan ikkita ildizni olish uchun kvadrat formuladan foydalanishimiz kerak.

\[x = \frac{{ - 7 \pm \sqrt {{{\left( 7 \right)}^2} - 4\left( 1 \right)\left( { - 1} \right)} }}{{2\left( 1 \right)}} = \frac{{ - 7 \pm \sqrt {53} }}{2}\]

Keyin biz funktsiyaning quyidagi uchta ildiziga ega bo'lamiz,

\[x = 0,\,\,\,\,\,\,\,\frac{{ - 7 + \sqrt {53} }}{2} = 0.140055,\,\,\,\,\,\,\,\frac{{ - 7 - \sqrt {53} }}{2} = - 7.140055\]