Asosiy tarkibga o'tish

1.10-bo'lim : Umumiy grafiklar

8. Grafik kalkulyatordan foydalanmasdan \(f\left( y \right) = {\left( {y - 1} \right)^2} + 2\) grafigini chizing.

Yechim

Bizning funktsiyamiz \(x = f\left( y \right)\) shaklida bo'lsa ham, biz ushbu grafikni chizishimizga yordam berish uchun algebraik o'zgarishlardan foydalanishimiz mumkin. Biroq, biz ehtiyot bo'lishimiz kerak va biz almashtiriladigan o'zgaruvchilar bilan ishlayotganimizni yodda tutishimiz kerak, shuning uchun transformatsiyalar ham o'zgaradi.

Bu holda, agar biz \(h\left( y \right)\) grafigini bilsak, \(h\left( {y + c} \right) + k\) grafigi oddiygina \(h\left( x \right)\) ning grafigi, agar \(c < 0\) bo‘lsa, \(c\) birliklari bilan yuqoriga siljiydi yoki \(c > 0\) bo‘lsa, \(c\) birliklari bilan pastga siljiydi va MATHBLOCK11 birliklari bilan o‘ngga siljiydi, agar MATHBLOCK11 \(k\) birliklari, agar \(k < 0\).

Shunday qilib, bizning holatlarimizda \(h\left( y \right) = {y^2}\), biz buni ko'rishimiz mumkin,

\[f\left( y \right) = {\left( {y - 1} \right)^2} + 2 = h\left( {y - 1} \right) + 2\]

va shuning uchun bizdan eskiz qilishimiz so'ralayotgan grafik \(h\left( y \right) = {y^2}\) ning 1 birlik yuqoriga va o'ngga 2 birlikka siljigan grafigi.

Mana \(f\left( y \right) = {\left( {y - 1} \right)^2} + 2\) grafigi va shuni yodda tutingki, transformatsiyani ko'rishga yordam berish uchun biz \(h\left( y \right) = {y^2}\) grafigida ham chizganmiz.

The graph of \(f\left( y \right) = {\left( {y - 1} \right)^2} + 2\), drawn as a solid red curve, along with the graph of \(h\left( y \right) = {y^2}\), drawn as a dashed gray curve.  Both are parabolas that open to the right.  The vertex of \(h\left( y \right)\) is at the origin and the vertex of \(f\left( y \right)\) is at (2,1), so the graph of \(f\left( y \right)\) is the graph of \(h\left( y \right)\) shifted right 2 units and up 1 unit.