Haqiqatan ham bu muammo bilan bu erda ko'p narsa qilish mumkin emas. Biz qilishimiz kerak bo'lgan narsa vektorning barcha komponentlarining chegarasini olishdir.

\[\begin{align*}\mathop {\lim }\limits_{t \to - 2} \left( {\frac{{1 - {{\bf{e}}^{t + 2}}}}{{{t^2} + t - 2}}\vec i + \vec j + \left( {{t^2} + 6t} \right)\vec k} \right) & = \mathop {\lim }\limits_{t \to - 2} \frac{{1 - {{\bf{e}}^{t + 2}}}}{{{t^2} + t - 2}}\vec i + \mathop {\lim }\limits_{t \to - 2} \vec j + \mathop {\lim }\limits_{t \to - 2} \left( {{t^2} + 6t} \right)\vec k\\ & = \mathop {\lim }\limits_{t \to - 2} \frac{{ - {{\bf{e}}^{t + 2}}}}{{2t + 1}}\vec i + \mathop {\lim }\limits_{t \to - 2} \vec j + \mathop {\lim }\limits_{t \to - 2} \left( {{t^2} + 6t} \right)\vec k = \require{bbox} \bbox[2pt,border:1px solid black]{{\frac{1}{3}\vec i + \vec j - 8\vec k}}\end{align*}\]

L'Hospital qoidasini unutmang! Bizga birinchi muddat uchun kerak edi.