Asosiy tarkibga o'tish

9.6-bo'lim : Qutb koordinatalari

13. Quyidagi qutb tenglamasining grafigini chizing.

\[r = 9\sin \theta \]
Yechim

Buni quyidagicha qayta yozishimiz mumkin:

\[r = 2\left( {\frac{9}{2}} \right)\sin \theta \]

va shuning uchun biz ushbu bo'limdagi eslatmalardan bilamizki, bu oddiygina radiusi \(\frac{9}{2}\) va markazi \(\left( {0,\frac{9}{2}} \right)\) bo'lgan doiradir.

Shunday qilib, bu funktsiyaning grafigi.

The graph of \(r = 9\sin \theta \).  It is a circle of radius \(\frac{9}{2}\) centered at \(\left( {0,\frac{9}{2}} \right)\), so it sits on the origin at the bottom and reaches up to \(y = 9\) at the top.