Asosiy tarkibga o'tish

1.6-bo'lim : Ratsional ifodalar

12. Quyidagi ifodada ko'rsatilgan amalni bajaring.

\[\frac{{x + 10}}{{{{\left( {3x + 8} \right)}^3}}} + \frac{x}{{{{\left( {3x + 8} \right)}^2}}}\]
Yechim

Bu ratsional ifoda uchun birinchi navbatda eng kichik umumiy maxraj kerak.

\[{\mbox{lcd : }}{\left( {3x + 8} \right)^3}\]

Esda tutingki, biz eng kichik umumiy maxrajni o'rnatishda faqat maxrajdagi har bir atama uchun eng yuqori quvvatni olamiz.

2-qadam

Endi har bir atamaning maxrajiga eng kichik umumiy maxrajni olish uchun uni tegishli miqdorga ko'paytiring.

\[\frac{{x + 10}}{{{{\left( {3x + 8} \right)}^3}}} + \frac{x}{{{{\left( {3x + 8} \right)}^2}}} = \frac{{x + 10}}{{{{\left( {3x + 8} \right)}^3}}} + \frac{{x\left( {3x + 8} \right)}}{{{{\left( {3x + 8} \right)}^2}\left( {3x + 8} \right)}}\]
3-qadam

Endi biz qilishimiz kerak bo'lgan narsa qo'shishni amalga oshirish va natijaning hisobini soddalashtirishdir.

\[\frac{{x + 10}}{{{{\left( {3x + 8} \right)}^3}}} + \frac{x}{{{{\left( {3x + 8} \right)}^2}}} = \frac{{x + 10 + 3{x^2} + 8x}}{{{{\left( {3x + 8} \right)}^3}}} = \require{bbox} \bbox[2pt,border:1px solid black]{{\frac{{3{x^2} + 9x + 10}}{{{{\left( {3x + 8} \right)}^3}}}}}\]