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3.2-bo'lim : Chiziqlar

11. \(\left( { - 7,2} \right)\) orqali o‘tadigan va \(3x - 14y = 4\) to‘g‘riga perpendikulyar bo‘lgan chiziq tenglamasini toping.

Yechim

Birinchidan, biz yangi chiziqning qiyaligini olishimiz kerak, i.e. \(\left( { - 7,2} \right)\) nuqtasi orqali chiziq. Biz bilamizki, bu chiziq \(3x - 14y = 4\) chizig'iga parallel va qiyaliklar bir-biriga manfiy o'zaro bo'lishi kerak.

Shuning uchun biz qilishimiz kerak bo'lgan narsa - ikkinchi chiziq tenglamasini qiyalik-kesish shakliga qo'yish va uning qiyaligini olish.

\[\begin{align*}3x - 14y & = 4\\ 14y & = 3x - 4\\ y & = \frac{3}{{14}}x - \frac{2}{7}\hspace{0.25in}:\hspace{0.25in}{m_2} = \frac{3}{{14}}\end{align*}\]

Shunday qilib, yangi chiziq qiyaligiga ega bo'lishi kerak,

\[{m_1} = - \frac{1}{{{m_2}}} = - \frac{1}{{{}^{3}/{}_{{14}}}} = - \frac{{14}}{3}\]
2-qadam

Endi bizda yangi chiziqning qiyaligi ham, yangi chiziq orqali nuqta ham bor, shuning uchun biz yangi chiziq tenglamasini yozish uchun chiziqning nuqta-qiyalik shaklidan foydalanishimiz mumkin.

\[y = 2 - \frac{{14}}{3}\left( {x - \left( { - 7} \right)} \right) = 2 - \frac{{14}}{3}\left( {x + 7} \right) = - \frac{{14}}{3}x - \frac{{92}}{3}\]