3.1-bo'lim : Grafikalash
6. Quyidagi tenglama uchun \(x\)-kesishmalarni va \(y\)-kesishmalarini aniqlang.
\[y = {x^2} + 6x - 7\]Yechim
Eslatib o'tamiz, \(y\)-kesishini topish uchun faqat \(x = 0\)-ni tenglamaga qo'shish va \(y\) ni hal qilish kerak. Bu tenglama uchun buni qilish,
\[\begin{align*}y & = {\left( 0 \right)^2} + 6\left( 0 \right) - 7\\ y & = - 7\end{align*}\]Bu tenglama uchun \(y\)-kesishmasi nuqta bo'ladi: \(\left( {0, - 7} \right)\).
2-qadam
\(x\)-kesishmasini topish \(y\)-kesishmasiga o'xshaydi. Biz faqat \(y = 0\)-ni ulab, \(x\)-ni hal qilamiz. Bu tenglama uchun buni qilish,
\[\begin{align*}0 & = {x^2} + 6x - 7\\ 0 & = \left( {x + 7} \right)\left( {x - 1} \right)\hspace{0.25in} \Rightarrow \hspace{0.25in} x = - 7,\,\,\,\,\,x = 1\end{align*}\]Bu tenglama uchun \(x\)-kesishmalar ikkita nuqtadir: \(\left( { - 7,0} \right)\) va \(\left( {1,0} \right)\).