GraphFunctions - 2-masala yechimi | MathModel.uz

3.5-bo'lim : Grafikalash funktsiyalari

2. Quyidagi funksiya grafigida kamida 4 ta tartiblangan juft nuqtalardan iborat jadval tuzing va funksiya grafigini chizish uchun jadvaldagi tartiblangan juftlardan foydalaning.

\[f\left( x \right) = \sqrt {x + 1} \]

Yechim

Ushbu funktsiya uchun biz grafikni biroz osonlashtirish uchun butun sonlar bo'lgan funktsiya qiymatlarini beradigan nuqtalardan foydalanamiz.

Mana biz ushbu muammoni hal qilishda foydalanadigan fikrlar jadvali.

$x$	$f\left( x \right)$	$\left( {x,y} \right)$
-1	0	$\left( { - 1,0} \right)$
0	1	$\left( {0,1} \right)$
3	2	$\left( {3,2} \right)$
8	3	$\left( {8,3} \right)$

2-qadam

Bu funksiyaning eskizi.

$The graph of $f\left( x \right) = \sqrt {x + 1} $. It starts at $\left( { - 1,0} \right)$ and increases as it moves to the right, rising steeply at first and then flattening out. The points from the table are marked and labeled on the graph and they are $\left( { - 1,0} \right)$, $\left( {0,1} \right)$, $\left( {3,2} \right)$ and $\left( {8,3} \right)$.$

\(x\)	\(f\left( x \right)\)	\(\left( {x,y} \right)\)
-1	0	\(\left( { - 1,0} \right)\)
0	1	\(\left( {0,1} \right)\)
3	2	\(\left( {3,2} \right)\)
8	3	\(\left( {8,3} \right)\)