ko'paytuvchilarga ajratishning dastlabki shakli quyidagicha bo'ladi:

\[\left( {y + \underline {\,\,\,\,\,} } \right)\left( {y + \underline {\,\,\,\,\,} } \right)\]

va 60 ning omillari,

\[\begin{array}{c} \left( { - 1} \right)\left( { - 60} \right) & \left( { - 2} \right)\left( { - 30} \right) & \left( { - 3} \right)\left( { - 20} \right) & \left( { - 4} \right)\left( { - 15} \right) & \left( { - 5} \right)\left( { - 12} \right) & \left( { - 6} \right)\left( { - 10} \right)\\ \left( 1 \right)\left( {60} \right) & \left( 2 \right)\left( {30} \right) & \left( 3 \right)\left( {20} \right) & \left( 4 \right)\left( {15} \right) & \left( 5 \right)\left( {12} \right)& \left( 6 \right)\left( {10} \right)\end{array}\]

Ba'zida biz hal qilishimiz kerak bo'lgan juda ko'p omillar mavjud. Ko'proq amaliyotga ega bo'lgach, siz bularning ko'pini o'z boshingizda qila boshlaysiz va aslida barcha omillarni yozishingiz shart emas.

2-qadam

Endi, yuqoridagi ro‘yxatdagi omillar juftligini eslab, 16 ni olish uchun qo‘shiladi. Shunday qilib, to‘g‘ri ko'paytuvchilarga ajratish shunday bo‘lishini ko‘ramiz,

\[{y^2} + 16y + 60 = \require{bbox} \bbox[2pt,border:1px solid black]{{\left( {y + 6} \right)\left( {y + 10} \right)}}\]