1.5-bo'lim : Ko'p nomlilarni ko'paytuvchilarga ajratish
12. Quyidagi ko‘phadni ko‘paytiring.
\[4{z^2} + 19z + 12\]Yechim
4 ta ijobiy omillarning ikkita to'plami mavjud va shuning uchun biz ko'paytuvchilarga ajratish uchun quyidagi ikkita mumkin bo'lgan dastlabki shakllardan biriga ega bo'lamiz.
\[\left( {2z + \underline {\,\,\,\,\,} } \right)\left( {2z + \underline {\,\,\,\,\,} } \right)\hspace{0.25in}\hspace{0.25in}\hspace{0.25in}\hspace{0.25in}\left( {4z + \underline {\,\,\,\,\,} } \right)\left( {z + \underline {\,\,\,\,\,} } \right)\]va 12 ning omillari,
\[\left( { - 1} \right)\left( { - 12} \right)\,\hspace{0.25in}\left( { - 2} \right)\left( { - 6} \right)\hspace{0.25in}\left( { - 3} \right)\left( { - 4} \right)\hspace{0.25in}\left( 1 \right)\left( {12} \right)\,\hspace{0.25in}\left( 2 \right)\left( 6 \right)\hspace{0.25in}\hspace{0.25in}\left( 3 \right)\left( 4 \right)\]2-qadam
Ba'zi sinov va xatoliklardan so'ng biz to'g'ri ko'paytuvchilarga ajratish bo'lishini ko'ramiz,
\[4{z^2} + 19z + 12 = \require{bbox} \bbox[2pt,border:1px solid black]{{\left( {4z + 3} \right)\left( {z + 4} \right)}}\]