5 ning faqat ikkita ijobiy omili bor, shuning uchun ko'paytuvchilarga ajratishning dastlabki shakli quyidagicha bo'ladi:

\[\left( {5x + \underline {\,\,\,\,\,} } \right)\left( {x + \underline {\,\,\,\,\,} } \right)\]

va -3 omillari,

\[\left( { - 1} \right)\left( 3 \right)\,\hspace{0.25in}\left( 1 \right)\left( { - 3} \right)\]

2-qadam

Ba'zi sinov va xatoliklardan so'ng biz to'g'ri ko'paytuvchilarga ajratish bo'lishini ko'ramiz,

\[5{x^2} + 14x - 3 = \require{bbox} \bbox[2pt,border:1px solid black]{{\left( {5x - 1} \right)\left( {x + 3} \right)}}\]