5.1-bo'lim : ko'phadlarni bo'lish
5. \(7{x^3} - 1\) ni \(x + 2\) ga bo‘lish uchun sintetik bo‘linishdan foydalaning.
Yechim
Bu erda sintetik bo'linish. Barcha raqamlarni tekshirishni sizga qoldiramiz.
\[\begin{array}{*{20}{r}}{\left. {\underline {\,{ - 2} \,}}\! \right| }\\{}\\{}\end{array}\,\,\,\,\begin{array}{*{20}{r}}7&0&0&{ - 1}\\{}&{ - 14}&{28}&{ - 56}\\\hline7&{ - 14}&{28}&{ - 57}\end{array}\]2-qadam
Unda javob shuki,
\[7{x^3} - 1 = \left( {x + 2} \right)\left( {7{x^2} - 14x + 28} \right) - 57\]E'tibor bering, biz javobning faqat bitta shaklini berdik (birinchi ikkita muammodan farqli o'laroq), chunki bu ko'pincha sintetik bo'linishdan foydalanganda bizga kerak bo'lgan shakl va bu usul berish uchun sozlangan shakldir.