5.1-bo'lim : ko'phadlarni bo'lish
4. \({x^3} + {x^2} + x + 1\) ni \(x + 9\) ga bo‘lish uchun sintetik bo‘linishdan foydalaning.
Yechim
Bu erda sintetik bo'linish. Barcha raqamlarni tekshirishni sizga qoldiramiz.
\[\begin{array}{*{20}{r}}{\left. {\underline {\,{ - 9} \,}}\! \right| }\\{}\\{}\end{array}\,\,\,\,\begin{array}{*{20}{r}}1&1&1&1\\{}&{ - 9}&{72}&{ - 657}\\\hline1&{ - 8}&{73}&{ - 656}\end{array}\]2-qadam
Unda javob shuki,
\[{x^3} + {x^2} + x + 1 = \left( {x + 9} \right)\left( {{x^2} - 8x + 73} \right) - 656\]E'tibor bering, biz javobning faqat bitta shaklini berdik (birinchi ikkita muammodan farqli o'laroq), chunki bu ko'pincha sintetik bo'linishdan foydalanganda bizga kerak bo'lgan shakl va bu usul berish uchun sozlangan shakldir.