1.3-bo'lim : Radikallar
1-6-masalalar uchun ifodani eksponensial shaklda yozing.
- \(\sqrt {3n} \)
- \(\sqrt[6]{{2y}}\)
- \(\sqrt[5]{{7{x^3}}}\)
- \(\sqrt[4]{{xyz}}\)
- \(\sqrt {x + y} \)
- \(\sqrt[3]{{{a^3} + {b^3}}}\)
7-12 muammolar uchun radikalni baholang.
- \(\sqrt {256} \)
- \(\sqrt[4]{{256}}\)
- \(\sqrt[8]{{256}}\)
- \(\sqrt[5]{{ - 1024}}\)
- \(\sqrt[3]{{ - 216}}\)
- \(\sqrt[3]{{343}}\)
13-22-muammolar uchun quyidagilarning har birini soddalashtiring. \(x\), \(y\) va \(z\) hammasi ijobiy deb faraz qiling.
- \(\sqrt {{z^5}} \)
- \(\sqrt[3]{{{z^5}}}\)
- \(\sqrt[3]{{16{x^{17}}}}\)
- \(\sqrt[6]{{128{y^{11}}}}\)
- \(\sqrt {{x^3}{y^{17}}{z^4}} \)
- \(\sqrt[4]{{{x^3}{y^{20}}{z^5}}}\)
- \(\sqrt[4]{{729{x^7}y\,{z^{13}}}}\)
- \(\sqrt[3]{{4{x^2}y}}\,\,\,\sqrt[3]{{10{x^5}{y^2}}}\)
- \(\sqrt {3x} \,\,\sqrt {6x} \,\,\sqrt {14x} \)
- \(\sqrt[4]{{2x{y^3}}}\,\,\,\sqrt[4]{{32{x^2}{y^2}}}\)
23 dan 26 gacha bo'lgan muammolar uchun quyidagi raqamlarning har birini ko'paytiring. \(x\) ijobiy deb faraz qiling.
- \(\left( {2\sqrt x + 4} \right)\left( {\sqrt x - 7} \right)\)
- \(\sqrt[3]{x}\left( {\sqrt[3]{x} + 2\sqrt[3]{{{x^4}}}} \right)\)
- \(\left( {\sqrt x + \sqrt {2y} } \right)\left( {\sqrt x - \sqrt {2y} } \right)\)
- \({\left( {\sqrt[4]{x} + \sqrt[4]{{{x^2}}}} \right)^2}\)
27-35-masalalar uchun maxrajni ratsionalizatsiya qiling. \(x\) va \(y\) ikkalasi ham ijobiy deb faraz qiling.
- \(\displaystyle \frac{9}{{\sqrt y }}\)
- \(\displaystyle \frac{3}{{\sqrt {7x} }}\)
- \(\displaystyle \frac{1}{{\sqrt[4]{x}}}\)
- \(\displaystyle \frac{{12}}{{\sqrt[5]{{3{x^2}}}}}\)
- \(\displaystyle \frac{2}{{4 - \sqrt x }}\)
- \(\displaystyle \frac{9}{{\sqrt {3y} + 2}}\)
- \(\displaystyle \frac{4}{{\sqrt 7 - 6\sqrt x }}\)
- \(\displaystyle \frac{{ - 6}}{{\sqrt {5x} + 10\sqrt y }}\)
- \(\displaystyle \frac{{4 + x}}{{x - \sqrt x }}\)
36-38 muammolar uchun bayonotning to'g'ri yoki noto'g'ri ekanligini aniqlang. Agar noto'g'ri bo'lsa, nima uchun noto'g'ri ekanligini tushuntiring.
- \(3{x^{\frac{1}{2}}} = \sqrt {3x} \)
- \(\sqrt[3]{{x + 6}} = \sqrt[3]{x} + \sqrt[3]{6}\)
- \(\sqrt[4]{{{x^2}}} = \sqrt x \)
- Yuqoridagi 13-35 muammolar uchun biz har doim o'zgaruvchilar ijobiy deb taxmin qilish uchun ko'rsatma qo'shdik. Nima uchun bu ko'rsatma qo'shilgan? Agar bizda bunday ko'rsatma bo'lmasa, muammolarga javoblar qanday o'zgaradi?